2p^2-5p^2-63p=0

Solution for 2p^2-5p^2-63p=0 equation:

2p^2-5p^2-63p=0

We add all the numbers together, and all the variables

-3p^2-63p=0

a = -3; b = -63; c = 0;
Δ = b2-4ac
Δ = -632-4·(-3)·0
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-63}{2*-3}=\frac{0}{-6}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+63}{2*-3}=\frac{126}{-6}
=-21
$